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x^2+13x+4=80
We move all terms to the left:
x^2+13x+4-(80)=0
We add all the numbers together, and all the variables
x^2+13x-76=0
a = 1; b = 13; c = -76;
Δ = b2-4ac
Δ = 132-4·1·(-76)
Δ = 473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{473}}{2*1}=\frac{-13-\sqrt{473}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{473}}{2*1}=\frac{-13+\sqrt{473}}{2} $
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